(Almost) Impossible Integrals, Sums, and Series (Problem Books in Mathematics)

(Almost) Impossible Integrals, Sums, and Series (Problem Books in Mathematics)

Matematika jam 12 lomba mat guys :v menang ga ya guys :v , menang 10 JT :v gw bagi serebu :v

q.

1!×7!!+9!
105×5!
1+2+3+4+5×15

Note : canda lh guys gw juga ga yakin untuk menang :v

jam 12 lomba mat guys :v menang ga ya guys :v , menang 10 JT :v gw bagi serebu :v

q.

1!×7!!+9!
105×5!
1+2+3+4+5×15

Note : canda lh guys gw juga ga yakin untuk menang :v

Jawaban:

1!×7!!+9!

=1×105+362,880

=105+362,880

=362,985

105×5!

=105×120

=12,600

1+2+3+4+5×15

=15×5+4+3+2+1

=75+4+3+2+1

=79+3+2+1

=82+2+1

=84+1

=85.

perkalian terlebih dahulu.

maaf kalo salah.

Jawaban:

1!×7!!+9! =

= 1 × (7×5×3×1) + (9×8×7×6×5×4×3×2×1)

= 1 × (35×3×1) + (72×7×6×5×4×3×2×1)

= 1 × (105×1) + (504×6×5×4×3×2×1)

= 1 × 105 + (3.024×5×4×3×2×1)

= 1 × 105 + (15.120×4×3×2×1)

= 1 × 105 + (60.480×3×2×1)

= 1 × 105 + (181.440×2×1)

= 1 × 105 + (362.880×1)

= 1 × 105 + 362.880

= 105 + 362.880

= 362.985 ☑

===========================================

105×5! =

= 105×(5×4×3×2×1)

= 105 × (20×3×2×1)

= 105 × (60×2×1)

= 105 × (120×1)

= 105 × 120

= 12.600 ☑

===========================================

1+2+3+4+5×15 =

= 1+2+3+4+(5×15)

= 1+2+3+4+75

= 3+3+4+75

= 6+4+75

= 10+75

= 85 ☑

Penjelasan dengan langkah-langkah:

Moga membantu :3

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