(3x²-5x²-8x+15)+(6x²+8x+13)
(3x²-5x²-8x+15)+(6x²+8x+13)
= (-2x²-8x+15)+(6x²+8x+13)
= (-2x²+6x²)-(-8x+8x)+(15+13)
ket: dikelompokkan sesuai suku/variabel
= 4x²+28
= 4 (x²+7)
Semoga Membantu
[answer.2.content](Almost) Impossible Integrals, Sums, and Series (Problem Books in Mathematics)
(Almost) Impossible Integrals, Sums, and Series (Problem Books in Mathematics)
(3x²-5x²-8x+15)+(6x²+8x+13)
= (-2x²-8x+15)+(6x²+8x+13)
= (-2x²+6x²)-(-8x+8x)+(15+13)
ket: dikelompokkan sesuai suku/variabel
= 4x²+28
= 4 (x²+7)
Semoga Membantu
[answer.2.content]