pada suhu dan tekanan tertentu volume dari 14 gram nitrogen adalah 14 liter
Massa N2 = 14 gr
V N2 = 14 liter
massa O2 = 16 gr
V N2 / mol N2 = V O2 / mol O2
V O2 = V N2 x mol O2/mol N2
V O2 = 14 x (16/32) / (14/28)
V O2 = 14 liter
(Almost) Impossible Integrals, Sums, and Series (Problem Books in Mathematics)
(Almost) Impossible Integrals, Sums, and Series (Problem Books in Mathematics)
Massa N2 = 14 gr
V N2 = 14 liter
massa O2 = 16 gr
V N2 / mol N2 = V O2 / mol O2
V O2 = V N2 x mol O2/mol N2
V O2 = 14 x (16/32) / (14/28)
V O2 = 14 liter